tag:blogger.com,1999:blog-8200098102909041178.post6900032167763533180..comments2024-03-24T09:12:10.872-04:00Comments on Shane Colton: Get down from there, flux. You're not DC. You're not even a real measured quantity.Shane Coltonhttp://www.blogger.com/profile/10603406287033587039noreply@blogger.comBlogger3125tag:blogger.com,1999:blog-8200098102909041178.post-69081870772954655472012-12-16T20:55:33.658-05:002012-12-16T20:55:33.658-05:00Thank you very much for you nice post!Thank you very much for you nice post!RadioZuohttps://www.blogger.com/profile/12231598229694977638noreply@blogger.comtag:blogger.com,1999:blog-8200098102909041178.post-31043839521297245052012-10-12T20:24:35.057-04:002012-10-12T20:24:35.057-04:00This is actually a question that requires a more d...This is actually a question that requires a more detailed answer. I am writing up a complete description of this sensorless method which will have the full answer. But here I will just give a short answer:<br /><br />The time constant should be significantly longer than the commutation period at the slowest speed for which sensorless operation is desired. So, if the electrical frequency is 40Hz at the lowest sensorless speed, for example, the filter time constant should be much larger than 1s/40. However, if the time constant is too long, then current sensor bias can lead to drift and instability. So those are the two constraints. <br /><br />More details to come. Thanks for asking!Shane Coltonhttps://www.blogger.com/profile/10603406287033587039noreply@blogger.comtag:blogger.com,1999:blog-8200098102909041178.post-18522889752976747982012-10-07T15:25:01.380-04:002012-10-07T15:25:01.380-04:00Hi,
How this filter time constant has to be calcu...Hi,<br /><br />How this filter time constant has to be calculated. <br /><br />Anonymousnoreply@blogger.com